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Jiayi Liu, 12/03/2013 10:05 AM

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h1. Method
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refer to workplanJul29.org.  Updated at Dec 3.
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y(r)=y0(1+r^2/θ^2_c)^{−(3β−1)/2}
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For β=1 case, we have: Y_{int}(r)=πθ^2_cy_0\ln[1+(r/θ_c)^2].
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For β=2/3 case, we have: Y_{int}(r)=πθ^2_cy_0\times2[\sqrt{1+(r/θ_c)^2}−1].
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For R500, it is normally 3 times of Rcore.
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h1. Source code
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h1. Result
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